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Chatterbox: Chirp at Cricket

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*rips up handful of math symbols and throws them at you *
Feel free to retaliate or guess me. 
submitted by the math thrower
(May 17, 2023 - 9:16 am)

*sings to the tune of 'Pop Goes The Weasle'* X equals negative-b, plus or minus square root, b-squared, minus 4ac all over 2a


submitted by Rainbow, age [Lost], Raise A Glass To Freedom!
(May 17, 2023 - 6:37 pm)

*joins in* x is equal to negative b, plus or minus the square root, of b squared minus 4ac, all over 2a!

Ahh yes the good old quadratic formula to pop-goes-the-weasel.

submitted by Scuttles
(May 18, 2023 - 6:47 am)

*joins you all* x is equal to -b, plus or minus the square root of b squared minus 4ac... all over 2a!

aah we just learned this in algebraaaaaa 

submitted by Wolfy, age 14, in math class lol
(May 22, 2023 - 10:11 am)
submitted by top
(May 17, 2023 - 6:44 pm)

*hides for fear of math symbols*

submitted by Poinsettia
(May 17, 2023 - 9:12 pm)

*runs in screaming*

*chucks a giant division sign at the nearest innocent bystander*

*runs out*

submitted by Phoenix Tears, age 14 she/her, Revolutionary Grape Jelly
(May 18, 2023 - 1:35 pm)

*jumps up and down excitedly*

Yes, yes, yes yes, this is exactly the place for me to talk about slope, which, if it is a proportional line, is y = mx, where y is the y value (commonly distance), m is the slope or rate of change, and x is most of the time the time (distance/time). Therefore, m (or k as it is sometimes called) can be found by solving y/x or y2 - y1 over x2 - x1, labeling the points on the graph from left to right and m = y/x. When the line is not proportional, the equation y = mx + b must be applied because b stands for the initial value, where the line crosses the y axis. It is not neccessary when the line is proportional and the y-intercept or initial value is 0. In order to graph any point on the line, use the equation y = mx + b, or y = b + mx, or mx + b = y, or b + mx = y or--(you get the idea)

*throws linear equations*  

submitted by Lyric, age Excluded, slope
(May 18, 2023 - 7:41 pm)

*throws trigonometric functions everywhere*

The trigonometric functions are used to solve right triangles in multiple cases. There are six functions, all functions of one of the nonright angles. The sine, abbreviated sin, is the side opposite the angle over the hypotenuse. The cosine, abbreviated cos, is adjacent over hypotenuse. The tangent, abbreviated tan, is opposite over adjacent. The secant, abbreviated sec, is hypotenuse over adjacent. The cosecant, abbreviated csc, is the hypotenuse over opposite. The cotangent, abbreviated either cot or ctn, is adjacent over opposite. We can thus use our algebra skills to solve for a side given we know one of the nonright angles. For example, the opposite side to an angle is the sine of that angle times the hypotenuse, or o/h times h where the hs cancel out to give just o. 
*throws all six trig functions for good measure*
*throws triangles*
submitted by the math thrower, age aka Sine, previously revealed
(May 21, 2023 - 10:30 am)